Nous Hermes 2 Yi 34b

Let's analyze the given information:

1. The 7th student wrote 20 verses.
2. Each student is supposed to write n verses plus twice as many verses as their class rank.

Now, let's set up an equation for the number of verses written by a student based on their rank and solve for n:

The 7th student (rank 6) wrote 20 verses. Let's represent this in terms of n:

Verses_written = n + 2 * (class_rank - 1)

For the 7th student, class rank is 6 and Verses_written is 20:

20 = n + 2 * (6 - 1)
20 = n + 2 * 5
20 = n + 10
10 = n

So the value of n is 10.<|im_end|>

Zephyr 7B

Analysis: The 7th student writes n verses and twice the number of class rank, i.e., 2n. So, the total number of verses written by the 7th student is (n + 2n) = 3n. Since the 7th student wrote 20 verses, we have:

20 = 3n

or n = 20/3. Hence, the value of n is 20/3.

Mixtral 8x7b v0.1 instruct

✅

First, let's analyze the problem. Robert asks his students to write poetry verses where each student writes n verses plus twice their class rank in verses. The 7th student wrote 20 verses, so we can create an equation using this information:
n + 2 * 7 = 20
Now let's solve for n:
n + 14 = 20
n = 6

Therefore, the value of n is 6.

Mistral 7B Instruct v0.3

 To find the value of n, we first need to determine how many verses the 7th student wrote beyond their rank. Since the 7th student wrote 20 verses and the 7th rank implies 6 other students before them, they wrote twice the number of students before them, or 2*6 = 12 additional verses.

Now, we know that the 7th student wrote a total of n + 12 verses. However, since they were supposed to write n verses according to the instructions, the remaining verses should be their class rank-based verses. So, the number of verses they wrote based on their rank is n.

Therefore, to find the value of n, we can set up the equation:

n + 12 = n + 2*(number of students before 7th rank)

Since there are 30 students in total, the number of students before the 7th rank is 30 - 7 = 23.

Substituting this into our equation:

n + 12 = n + 2*23

Solving for n:

n = 23 - 12

So, the value of n is 11.

Llama 3.1 8B Instruct

✅

✅

Let's break down the information given in the problem. The 7th student wrote 20 verses, and this student is supposed to write n verses, plus twice as many verses as their class rank (which is 7).

Let's denote the number of verses the student is supposed to write as n, and the number of verses that is twice the class rank as 2 × 7 = 14. We know that the total number of verses the student wrote is 20.

We can set up an equation to represent the situation:

n + 14 = 20

Now, let's solve for n. To isolate n, we need to subtract 14 from both sides of the equation:

n = 20 - 14
n = 6

So, the value of n is 6.

 

n = 6

TinyLlama v1.0 chat 1.1b

The correct value of n is (20 + 1) = 21.

CodeLlama 13b Instruct

The number of verses written by the 7th student is given as 20. Since each student writes n verses and twice as many as their class rank, we can set up an equation:

Number of verses written = 2x + n
where x is the class rank of the student and n is the number of verses each student writes.

We know that the 7th student wrote 20 verses so we can substitute this value into our equation.

20 = 2(6) + n
Subtracting twice as many verses as their class rank from both sides gives us:
n = 4
Hence, the number of verses each student writes is 4.

Please let me know if you have any further questions. I'm here to help!

Vicuna 33b Chat

 Let's analyze the problem:

1. The students need to write n verses as a base.
2. They also have to write twice as many verses as their class rank.
3. We are given that the 7th student wrote 20 verses, so we can use this information to find the value of n.

We can set up an equation using the information:

n + 2 \* (class\_rank - 1) = 20

Since the 7th student has a class rank of 7, we can substitute it into the equation:

n + 2 \* (7 - 1) = 20
n + 12 = 20
n = 8

So, the value of n is 8.

Llama 3 8B Instruct

✅

✅

Let's break down the problem step by step!

Let the number of verses the 7th student wrote be equal to the total number of verses, T. We know that the total number of verses is the sum of the number of verses, n, and twice the class rank.

T = n + 2(7)

Since the 7th student wrote 20 verses, we can set up the equation:

20 = n + 2(7)

Now, let's simplify the equation:

20 = n + 14

Subtract 14 from both sides:

6 = n

Therefore, the value of n is 6.

_____________________________________

n = 6

Kunoichi DPO v2 7B

✅

 Let's analyze the problem step-by-step:

1. Each student is supposed to write n verses.
2. Each student also writes twice as many verses as their class rank.
3. We are given that the 7th student wrote 20 verses.

Let's denote the class rank as r and the number of verses a student writes as V. From the problem, we have:

V = n + 2r (equation 1)

We are given that the 7th student wrote 20 verses, so:

20 = n + 2(7)  (since r = 7)

Now, we can solve for n:

20 = n + 14
n = 20 - 14
n = 6

So, the value of n is 6. Each student, including the 7th one, is supposed to write 6 verses, plus twice as many verses as their class rank. But in this specific case, the 7th student wrote only the additional 14 verses (2*7).</s>

Claude 3.5 Sonnet

✅

✅

Let's approach this problem step-by-step:

1. Let's define our variables:
   n = the base number of verses each student is supposed to write
   r = the student's class rank

2. We're given that the total number of verses a student writes is:
   Total verses = n + 2r

3. We know that for the 7th student:
   - Their rank (r) is 7
   - They wrote 20 verses in total

4. Let's plug this information into our equation:
   20 = n + 2(7)

5. Simplify the right side of the equation:
   20 = n + 14

6. To solve for n, subtract 14 from both sides:
   20 - 14 = n + 14 - 14
   6 = n

Therefore, the value of n is 6.

n = 6

StableLM Zephyr 3B

Let's denote the number of verses the student writes as "n" and the number of extra verses due to their class rank as "2 * (rank - 1)" for the 7th student. Since the 7th student wrote 20 verses, we have the equation:

20 = n + 2 * (7 - 1)

Now, let's solve the equation step-by-step:

1. Simplify the equation by distributing the 2:
   20 = n + 2 * 6

2. Combine the terms:
   20 = n + 12

3. Subtract 12 from both sides:
   8 = n

So, the value of n is 8. The 7th student wrote 8 verses.

The correct answer is n = 8.<|endoftext|>

Mixtral 11bx2 MoE 19b

✅

Let's denote the number of verses the 7th student would write based on "n" as "x". This is because "x" = "n" + 2(7).
We are given that the 7th student wrote 20 verses. So, we have the equation 20 = "n" + 14.
Now, let's solve for "n":
20 = "n" + 14
Subtract 14 from both sides:
6 = "n"
The value of "n" is 6.
The answer is: 6</s>

Gemma 7b IT

**Analysis:**

* The number of verses written by each student is n plus twice the number of verses written by the student's class rank.
* The 7th student wrote 20 verses.
* Therefore, the value of n is equal to the number of verses written by the student's class rank minus two.

**Answer:**

The value of n is 4.<eos>

Gemma 2b IT

Let n be the class rank. Then, the number of verses written by each student is n + 2.

If the 7th student wrote 20 verses, we have:

n + 2 = 7

Solving for n, we get:

n = 5

Therefore, the class rank is 5, and n = 7.<eos>

Hermes 2 Pro Mistral 7B

✅

Let's break down the information given:

1. Each student is supposed to write n verses.
2. Each student is also supposed to write twice as many verses as their class rank.
3. The 7th student wrote 20 verses.

Since the 7th student wrote 20 verses, we can represent this as: n + 2*7 = 20.

Simplifying the equation, we have: n + 14 = 20.

Now, we can solve for n:

n = 20 - 14
n = 6

So, the value of n is 6.<|im_end|>

GPT 4o mini

✅

✅

Let's analyze the problem step by step.

1. **Understanding the Variables**:
   - Let \( n \) be the number of verses each student is supposed to write.
   - Each student also writes additional verses based on their class rank. The rank of the 7th student is 7.

2. **Verses Written by the 7th Student**:
   - According to the problem, the 7th student wrote a total of 20 verses. 
   - The total verses written can be represented as:
     \[
     \text{Total Verses} = n + 2 \times \text{(Class Rank)}
     \]
   - For the 7th student, this becomes:
     \[
     20 = n + 2 \times 7
     \]

3. **Setting Up the Equation**:
   - Substitute the class rank into the equation:
     \[
     20 = n + 14
     \]

4. **Solving for n**:
   - To isolate \( n \), subtract 14 from both sides:
     \[
     20 - 14 = n
     \]
     \[
     n = 6
     \]

Thus, the value of \( n \) is:

6

Mistral Nemo Instruct 2407

✅

✅

Let's break down the information given:

1. Each student writes n verses.
2. Each student also writes twice as many verses as their class rank.
3. The 7th student wrote 20 verses.

We can set up an equation to represent this situation. Let's use r to represent the number of verses a student writes based on their class rank (which is twice their rank). So, if the student is in the 7th position, their rank is 7, and they write 2r verses.

The total number of verses the 7th student wrote is the sum of the fixed number of verses (n) and twice their rank (2r):
n + 2r = 20

Since the 7th student's rank is 7, we can substitute 7 for r:
n + 2(7) = 20
n + 14 = 20

Now, we can solve for n:
n = 20 - 14
n = 6

So, the value of n is 6.

Final answer: n = 6

H2O Danube 1.8b Chat

n = 7 + 2 * (7 - 2) = 7 + 2 * 5 = 7 + 10 = 17</s>

Neural Hermes 2.5 7B

✅

Let's analyze the problem step by step.

1. Each student is supposed to write n verses.
2. They also write twice as many verses as their class rank.
3. The 7th student wrote 20 verses.

Now, let's find the expression for the total number of verses written by the 7th student. According to the problem, the 7th student wrote twice as many verses as their class rank, which is 7. So, they wrote 2 * 7 = 14 verses due to their rank. They also wrote n verses as per the initial condition. Therefore, the total number of verses written by the 7th student is 14 + n.

Given that the 7th student wrote 20 verses, we can set up an equation:

14 + n = 20

Now, let's solve for n:

n = 20 - 14
n = 6

So, the value of n is 6.<|im_end|>

Nous Hermes 2 SOLAR 10.7B

✅

Let's first analyze the information given:

1. Each student writes n verses.
2. The 7th student wrote 20 verses.
3. The 7th student wrote twice as many verses as the number of their class rank (2 * 7 = 14).

Now, let's set up an equation to represent the relationship between the number of verses the 7th student wrote (20) and the number of verses they should have written based on their class rank (14):

20 = n + 14

Now, let's solve for n:

n = 20 - 14
n = 6

So, the value of n is 6.<|im_end|>

Mixtral 34x2 MoE 60b

✅

Let's break down the problem step-by-step:

Step 1: Understand the given information.
We are told that each student writes n verses, plus twice as many verses as their rank in class. The 7th student wrote 20 verses.

Step 2: Set up an equation based on the given information.
Let's use S to represent the total number of verses written by the student with rank r (in this case, r = 7). According to the problem, the equation is:
S = n + 2r

Step 3: Use the given information to find a relationship between n and r.
We know that when r = 7 and S = 20, so we can substitute these values into our equation:
20 = n + 2(7)

Step 4: Simplify and solve for n.
Now let's simplify the equation further:
20 = n + 14
To isolate n, subtract 14 from both sides of the equation:
6 = n

Therefore, the value of n is 6.

Phi 3 Mini 4k Instruct

✅

To find the value of n, we first need to establish the relationship between the number of verses written by the 7th student and the given information. The 7th student wrote twice as many verses as their class rank, plus n verses.

Let's denote the number of verses written by the 7th student as V, their class rank as R, and the number of verses written per n as n. We can then form the equation:

V = 2R + n

We are given that the 7th student wrote 20 verses, so V = 20. And since the 7th student's rank is 7, we have R = 7.

Substituting these values into the equation:

20 = 2(7) + n

Now, we can solve for n:

20 = 14 + n
n = 20 - 14
n = 6

So, the value of n is 6.

Answer: n = 6<|end|>

H2O Danube 3 4b Chat

n = 3

Starling LM 7B Beta

✅

 Let's analyze the problem step by step:

1. Each student is supposed to write n verses.
2. Each student is also supposed to write twice as many verses as their class rank.

We are given that the 7th student wrote 20 verses. Let's denote the class rank as 'r' and the number of verses written by the student with rank 'r' as 'v(r)'. We have:

v(7) = 20 (given)

Now, we need to find the relationship between 'n' and 'r' for the number of verses written by a student. We know that each student writes 'n' verses and '2r' additional verses:

v(r) = n + 2r

For the 7th student, we have:

v(7) = n + 2(7)
20 = n + 14

Now, we can solve for 'n':

n = 20 - 14
n = 6

So, the value of 'n' is 6. Each student, including the 7th student, is supposed to write 6 verses, plus twice as many verses as their class rank.<|end_of_turn|>

Claude 3 Haiku

✅

✅

To solve this problem, we need to find the value of n, which represents the number of verses each student is supposed to write.

Given information:
- Each student is supposed to write n verses, plus twice as many verses as the number of their class rank.
- The 7th student wrote 20 verses.

Let's represent the 7th student's class rank as r.

According to the problem statement, the 7th student wrote:
n + 2r verses

We know that the 7th student wrote 20 verses, so we can set up an equation:
n + 2r = 20

Since the 7th student's class rank is 7, we can substitute r = 7 into the equation:
n + 2(7) = 20
n + 14 = 20
n = 6

Therefore, the value of n, the number of verses each student is supposed to write, is 6.

n = 6

Claude 3 Sonnet

✅

✅

To solve this problem, we need to set up an equation based on the given information and then solve for the value of n.

Given information:
- Each student is supposed to write n verses.
- Each student is also supposed to write twice as many verses as their class rank.
- The 7th student wrote 20 verses.

Let's represent the number of verses written by the 7th student as an equation:
n + 2 × 7 = 20

Step 1: Simplify the equation by evaluating the expression on the right-hand side.
2 × 7 = 14

Step 2: Substitute the simplified expression into the equation.
n + 14 = 20

Step 3: Subtract 14 from both sides of the equation to isolate n.
n + 14 - 14 = 20 - 14
n = 6

Therefore, the value of n, which represents the number of verses each student is supposed to write, is 6.

Answer: n = 6

Gemma 2 9B IT

✅

✅

Let's break down this problem step-by-step:

1. **Define the variables:**
   * Let 'n' represent the base number of verses each student is supposed to write.

2. **Set up the equation:**
   * The 7th student wrote 20 verses, which can be represented as: n + 2 * 7 = 20

3. **Solve for 'n':**
   * Simplify the equation: n + 14 = 20
   * Subtract 14 from both sides: n = 6 


n = 6

Claude 3 Opus

✅

✅

Let's approach this problem step by step:

1. Understand the given information:
   * Each student writes n verses, plus twice their class rank.
   * The 7th student wrote 20 verses.

2. Let's represent the number of verses written by the 7th student using an equation:
   * Number of verses = n + 2 × class rank
   * 20 = n + 2 × 7

3. Simplify the equation:
   * 20 = n + 14

4. Solve the equation for n:
   * Subtract 14 from both sides of the equation:
     20 - 14 = n + 14 - 14
     6 = n

Therefore, the value of n is 6.

n = 6

Gemini Pro 1.0

✅

✅

Let's denote the number of verses each student is supposed to write as n.

According to the given information, each student is supposed to write n verses, plus twice as many verses as the number of their class rank. So, for the 7th student, the total number of verses he is supposed to write is:

n + 2 * 7 = 20

Simplifying the equation:

n + 14 = 20

Subtracting 14 from both sides:

n = 20 - 14

n = 6

Therefore, the value of n is 6.
```
n = 6
```

Gemini 1.5 Pro

✅

✅

## Analyzing the Poetry Problem

We know the total number of verses written by the 7th student is 20. This total is composed of a fixed number of verses (n) and a variable number of verses based on their class rank. Since the student is 7th, they have to write 2 * 7 = 14 verses based on their rank.

We can set up an equation to represent this:

Total Verses = Fixed Verses + Rank-Based Verses
20 = n + 14

Solving for n:

n = 20 - 14 

Therefore:

n = 6 

StableLM 2 1.6B Chat

To find the value of n, we need to determine how many verses the 7th student is supposed to write based on the given information. According to the problem, the 7th student wrote 7 verses (the given number of "A" class rank), and twice as many as that number are to be added. Therefore, the 7th student is supposed to write 2 * 7 = 14 additional verses.

Now, we can find the total number of verses the 7th student is supposed to write by adding the given 7 verses and the additional 14 verses: 7 + 14 = 21 verses.

Given that the 7th student wrote 21 verses, we can now find the value of n by using the given number of "A" class rank as 7. The problem states that each student is supposed to write n verses, including twice as many verses as their class rank. So, the equation becomes:

n = 7 (class rank) + 2 * 7 (additional verses)

Simplifying the equation, we get:

n = 7 + 14

n = 21

Therefore, the value of n is 21, and the 7th student is supposed to write 21 verses in total, including the given 7 verses and the additional 14 verses.

Mistral 7B Instruct v0.2

✅

✅

 To find the value of n, we first need to determine how many verses the 7th student wrote based on his class rank. Since he is the 7th student, his class rank is 7. According to the problem, he wrote 20 verses. So, the number of verses the 7th student wrote is:

Verses written by the 7th student = n + 2 * Class rank
20 = n + 2 * 7

Now we solve for n:

20 = n + 14
n = 20 - 14
n = 6

So, each student is supposed to write 6 verses, plus twice as many verses as their class rank.

The value of n is 6.

Gemma 2 27B IT

✅

✅

Let's break down this problem step-by-step:

* **Understand the problem:** Each student writes a base number of verses (n) plus twice their class rank. We know the 7th student wrote 20 verses.

* **Set up an equation:** Let's represent the 7th student's verses with the equation: n + 2 * 7 = 20

* **Solve for n:** 
    * n + 14 = 20
    * n = 20 - 14
    * n = 6


Therefore, the value of n is: 6

Gemma 1.1 7b IT

**Analysis:**

Let x be the class rank of the student. The number of verses written is n + 2x. The 7th student wrote 20 verses, so:

$$n + 2x = 20$$

**Solution:**

Solving for n, we get:

$$n = 20 - 2x$$

**Answer:**

$$n = 20 - 2x$$

Gemma 1.1 2B IT

✅

**Analysis:**

Let n be the number of students in Robert's class.

According to the problem, each student writes n verses and twice as many verses as their class rank. Therefore, the number of verses written by the 7th student would be 20, which implies:

n + 2(7) = 20

**Solution:**

n = 20 - 14
n = 6

Therefore, the value of n is 6.

GPT-4 Turbo 0125-preview

✅

✅

To find the value of \(n\), let's break down the information given:

1. Each student writes \(n\) verses.
2. Each student also writes twice as many verses as their class rank. For the 7th student, this means \(2 \times 7 = 14\) additional verses.
3. The 7th student wrote a total of 20 verses.

Given that the total number of verses written by the 7th student includes the base number of verses (\(n\)) plus twice their class rank (14 verses), we can set up the following equation to solve for \(n\):

\[n + 2 \times 7 = 20\]

\[n + 14 = 20\]

Subtracting 14 from both sides to solve for \(n\):

\[n = 20 - 14\]

\[n = 6\]

Therefore, the value of \(n\) is 6.

GPT-3.5 Turbo 0125

✅

Let's break down the information given:
- The 7th student wrote 20 verses
- The number of verses written by each student is n + 2*(student's class rank)

Since the 7th student wrote 20 verses, we can use the formula:
20 = n + 2*(7)

Simplify the equation:
20 = n + 14
n = 20 - 14
n = 6

Therefore, the value of n is 6.

Llama 3 70B

✅

✅

Let's break down the problem step by step!

Let the 7th student's class rank be 7. Since they wrote 20 verses, we can set up an equation based on the given information:

Number of verses = n + (2 × Class rank)
⇒ 20 = n + (2 × 7)

Now, let's simplify the equation:

20 = n + 14
Subtract 14 from both sides:
20 - 14 = n
6 = n

So, the value of n is:

n = 6

GPT-4 Turbo 0409

✅

To find the value of \( n \), we start by analyzing the information given:

1. Each student writes \( n \) verses.
2. Each student also writes an additional \( 2 \times \) their class rank number of verses.

For the 7th student:
- The class rank is 7.
- The total number of verses written by the 7th student is 20.

The formula for the total number of verses written by the 7th student can be expressed as:
\[ n + 2 \times \text{(class rank)} = \text{total verses} \]
Substituting the known values:
\[ n + 2 \times 7 = 20 \]
\[ n + 14 = 20 \]
\[ n = 20 - 14 \]
\[ n = 6 \]

Thus, the value of \( n \) is 6.

Command-R v01

✅

The number of extra verses the student must write is twice the class rank, so the 7th student wrote 2 * 7 = 14 extra verses. 

The total number of verses written is then N + 14. We can substitute this with the given information: 20 = N + 14. 

Solving for N, we get N = 6. 

The value of n is therefore 6.

Hermes 2 Pro Llama 3

✅

Let's first consider the information given in the problem:

1. Each student writes n verses.
2. Each student also writes twice their class rank in verses.
3. The 7th student wrote 20 verses.

We can set up an equation using this information:

n (number of verses per student) + 2 * (class rank of the student) = total number of verses written by the student

For the 7th student, we can plug in the given values:

n + 2 * 7 = 20

Solving for n:

n + 14 = 20
n = 6

So, the value of n is 6. The 7th student wrote 6 verses plus twice their class rank (which is 14) to reach a total of 20 verses.

GPT-4o

✅

✅

To solve for \( n \), let's start by setting up the equation based on the given information.

Each student is supposed to write \( n \) verses plus twice their class rank. For the 7th student, this can be expressed as:
\[ n + 2 \times 7 \]

According to the problem, the 7th student wrote 20 verses. Therefore, we can set up the following equation:
\[ n + 2 \times 7 = 20 \]

First, simplify the multiplication:
\[ n + 14 = 20 \]

Next, solve for \( n \) by isolating it on one side of the equation. Subtract 14 from both sides:
\[ n = 20 - 14 \]
\[ n = 6 \]

Thus, the value of \( n \) is:
\[ n = 6 \]

Phi 3 Mini 4k Instruct (2024-07-01)

✅

✅

Let's start by breaking down the given information. We know that Robert's students have to write n verses and twice as many verses as the number of their class rank. Let's represent the class rank of the student as r.

According to the problem, the 7th student wrote 20 verses. So, we can set up the following equation:

n + 2r = 20

Now, we need to find the value of n. Since the student is the 7th in the class, r = 7. Let's substitute r with 7 in the equation:

n + 2(7) = 20

Now, we can simplify and solve for n:

n + 14 = 20
n = 20 - 14
n = 6

So, the value of n is 6.

The correct answer is: n = 6.

Gemini 1.5 Flash

✅

✅

Let's break down the problem:

* The 7th student's verses are calculated as n (verses for everyone) + 2 * (class rank)
* We know the 7th student wrote 20 verses.

Now we can set up an equation:

n + 2 * 7 = 20

Simplifying the equation:

n + 14 = 20

Subtracting 14 from both sides:

n = 6

Therefore, the value of n is **6**. 

Hermes 2 Theta Llama 3 8B

✅

✅

Let's break down the problem step by step.

The 7th student wrote 20 verses. We know that each student writes n verses, plus twice as many verses as their class rank. So, for the 7th student, this can be written as:

n + 2 * 7 = 20

Simplifying the equation, we get:

n + 14 = 20

Now, let's solve for n:

n = 20 - 14
n = 6

So, the value of n is 6. 

Final Answer:
n = 6

SFR Iterated DPO Llama 3 8B R

Step 1:  To solve this problem, we first need to understand the given information and translate it into an equation.
Step 2:  The 7th student wrote 20 verses, which can be represented as 7n + (2 * 7) = 20, where 7n represents the number of initial verses (n) and 2 * 7 represents twice the student's class rank.
Step 3:  Now, we can solve for n by rearranging the equation: 7n + 14 = 20.
Step 4:  Subtracting 14 from both sides gives us 7n = 6.
Step 5:  Finally, we divide both sides by 7 to solve for n: n = 6 / 7.
Step 6:  Therefore, the value of n is 6 / 7.

Answer:
n = 6/7

Yi 1.5 6B Chat

✅

To solve this problem, we need to determine the value of n, which represents the number of verses each student is supposed to write, according to the given instructions.

The instructions state that each student is supposed to write n verses, plus twice as many verses as the number of their class rank. This can be written as an equation:

Number of verses = n + 2 * (class rank)

We know that the 7th student wrote 20 verses. Let's substitute the class rank with 7 and the number of verses written by the 7th student into the equation:

20 = n + 2 * 7

Now, let's solve for n:

20 = n + 14

Subtract 14 from both sides of the equation:

20 - 14 = n

n = 6

So, the value of n is 6. Each student is supposed to write 6 verses, plus twice as many verses as their class rank.<|im_end|>

Yi 1.5 9B Chat

✅

✅

Let's analyze the information given and set up an equation to solve for n, the number of verses each student is supposed to write without considering their class rank.

According to the problem, each student writes:
- n verses (a fixed number of verses)
- twice as many verses as their class rank.

The 7th student, for instance, writes n verses plus twice the number of their rank, which is 7. Therefore, the total number of verses the 7th student writes can be represented as:
n + 2 * 7 = 20 verses.

Now, let's solve for n:
n + 14 = 20.

Subtract 14 from both sides to isolate n:
n = 20 - 14,
n = 6.

Therefore, the value of n, the number of verses each student is supposed to write without considering their class rank, is 6.

The answer is 6.<|im_end|>

Yi 1.5 34B Chat

✅

Let's analyze the given information and set up an equation to solve for n.

We know that each student writes n verses plus twice as many verses as their class rank. The 7th student, therefore, writes n verses plus twice 7 verses.

The equation representing the total number of verses written by the 7th student is:
\[ n + 2 \times 7 = 20 \]

Now, let's solve for n step by step:

1. Simplify the equation:
\[ n + 14 = 20 \]

2. Subtract 14 from both sides to isolate n:
\[ n = 20 - 14 \]

3. Calculate n:
\[ n = 6 \]

Therefore, the value of n is 6.

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**The answer is n = 6.<|im_end|>

Llama 3 Refueled

Let's denote the number of verses the 7th student wrote as x. According to the given information, the 7th student wrote 20 verses, which is twice the number of their class rank. This means the class rank of the 7th student is 20/2 = 10. 

Now, let's denote the number of verses the 1st student wrote as n. According to the given information, the 1st student wrote n + 2 * 10 = n + 20 verses. 

Since the 7th student's class rank is 10, they are the 10th student. Therefore, the number of verses they wrote is n + 2 * 10 = 20. 

Substituting the known values, we have: n + 20 = 20. 

Solving for n, we have: n = 0. 

However, this result does not make sense, as a student cannot write 0 verses. There must be a mistake in the given information or the problem statement. Please double-check the given information and the problem statement.