Mixtral 34x2 MoE 60b

Score051015202527Size (bn params, log scale)0.5110101001000Mixtral 34x2 MoE 60b

Score:

17

63.0%

Strict score:

5

18.5%

Family:

Mistral

Size:

60B parameters

License:

CC by NC 4.0

Quant type:

Q4 K M

Question

Correct

Strict Correct

Response

RCS4

RCS5

SC1

.

Elena offered to lend Sofie one of her extra swimsuits so they could go swimming together that day.

SC2



Ben took off his hat and used it as the missing pawn.

SC4



MISSING CONTENT: Jane noticed that her phone was completely dead.

SC5



Mia remembered that the storage building was a good place to store balls. She suggested they check there for one to use in their game.

RCS1

RCS2



C) shifting responsibility for the costs of recycling

RCS3

RCL1



B) Short and dark with a big mustache and big hands

LG3

 must be true
Let's analyze the given statements:
1) All employees of Duluth Paper received a bonus this year.
2) Andrés did not receive a bonus this year.
Since both statements are assumed to be true, we can deduce that Andrés is not an employee of Duluth Paper based on statement 1 and his lack of bonus from statement 2 (as per the first statement, only employees of Duluth Paper would receive bonuses).

The correct answer is: C) Andrés was not an employee of Duluth Paper this year

MW4



Let's start by setting up the equations for the perimeter of a rectangle: 2(length + width) = Perimeter.
Since the length is four times the width, we can represent the length as 4w and the width as w (where 'w' stands for the width).
Now let's plug these values into the equation: 2(4w + w) = 60.
Simplify the equation by combining like terms within the parentheses: 2(5w) = 60, or 10w = 60.
Finally, divide both sides of the equation to solve for 'w': w = 60/10 = 6. Therefore, the width of the garden is 6 feet.

RCL3



D) the arrangement of her hair

RCL4


E) intensity of a person's feelings for another
--------------
The correct answer is E, the intensity of a person's feelings for another. The author uses this repetition to highlight Liz Coates' strong and numerous positive feelings towards Jim Gilmore. She likes many aspects about him, from his appearance and mannerisms to how other people perceive him. This technique helps portray her fondness or admiration for him in a clear and compelling way.

RCL5


E) Illustrate two peoples' contrasting perspectives on a person

LG1


Let's analyze the given information and each option step by step:

1. "All of Lisa's sisters can bake." - This statement tells us that every sister of Lisa has a baking ability.

Now let's examine each option:

(A) If Jane cannot bake, then she is not Lisa's sister - This option doesn't follow from the given information. The fact that Jane cannot bake does not necessarily mean she is not Lisa's sister. She could still be Lisa's sister and not know how to bake.

(B) If Sarah can bake, then she is not Lisa's sister - This statement contradicts the initial one because it assumes that there exists a person (Sarah) who can bake but is not Lisa's sister. However, according to our given information, all of Lisa's sisters can bake.

(C) If Mary can bake, then she is Lisa's sister - This option also doesn't follow from the given information. The fact that Mary can bake does not necessarily mean she is Lisa's sister. She could still be unrelated to Lisa and know how to bake.

(D) If Emma is not Lisa's sister, then she cannot bake - This statement assumes a necessary connection between being related to Lisa and having the ability to bake. However, this information is not provided in the given statements. It may very well be that someone who is not Lisa's sister can still know how to bake, or vice versa.

(E) None of these - Since none of the other options are necessarily true based on the given statement, this option must be correct. 

Therefore, after considering each statement and option, I conclude that:

(E) None of these

LG2


Based on the given statements, we can draw a few conclusions:
- All members of the chess team are also in the robotics club.
- No members of the basketball team are in the chess team.

Let's analyze each option:
(A) If Izak is in the robotics club, it doesn't necessarily mean he isn't on the basketball team. We can only conclude that if Izak is on the chess team, then he cannot be on the basketball team. This statement is not true based solely on the given information.
(B) If Jerry is in the robotics club, it means he must also be part of the chess team since all members of the chess team are in the robotics club. This statement is true based on the given information.
(C) If Lisa is on the basketball team, we know from the second statement that she cannot be a member of the chess team. However, it doesn't necessarily mean she isn't a member of the robotics club. The given statements do not provide enough information to determine her involvement in other clubs. This statement is not true based solely on the given information.
(D) If Sanjit is on the chess team, we know from the first statement that he must also be part of the robotics club. However, this does not provide any information about his involvement in basketball. The statement doesn't follow from the given information.
(E) If Seong-Jin is not in the robotics club, then it means he cannot be a member of the chess team since all members of the chess team are part of the robotics club. This statement is true based on the given information.

Based on our analysis:
(B) and (E) must be true. However, we can only choose one answer. Since option (E) provides more specific information about Seong-Jin's involvement in chess than option (B) does for Jerry, we will select (E) as the correct answer.
The answer is: (E) If Seong-Jin is not in the robotics club, then he is not on the chess team

LG4



The daughter is located in Mexico.

LG5



To answer the question, we need to analyze the given information and draw conclusions. 

1. We know that the person in Britain has the broken sword.
2. The son is not in Denmark.
3. The family member in Egypt has the family tree.
4. The mother has the silver watch but isn't in Mexico.
5. The grandmother has the gold doubloon and is either in Denmark or Canada. We are given that she is in Denmark.

Now, we need to find out where the mother is. Since the grandmother is in Denmark (and therefore not in Canada), the person in Canada must be the mother. 

So, the correct answer is: The Mother is in Canada.

LO1



□. ▲ ◆ ★

LO2



The correct order is: ★ ◆ ● ▲

LO3



★, ▲, ●, ◆

LO4

MW1


Let's break down the problem step-by-step:

Step 1: Understand the given information.
We are told that each student writes n verses, plus twice as many verses as their rank in class. The 7th student wrote 20 verses.

Step 2: Set up an equation based on the given information.
Let's use S to represent the total number of verses written by the student with rank r (in this case, r = 7). According to the problem, the equation is:
S = n + 2r

Step 3: Use the given information to find a relationship between n and r.
We know that when r = 7 and S = 20, so we can substitute these values into our equation:
20 = n + 2(7)

Step 4: Simplify and solve for n.
Now let's simplify the equation further:
20 = n + 14
To isolate n, subtract 14 from both sides of the equation:
6 = n

Therefore, the value of n is 6.

MW2


Using the given operation ◘, we can find the value of 4 ◘ 3 by plugging in the numbers into the equation.

So, (4) ◘ (3) = 2(4) - 3(3) + 1.

Now, let's perform the calculations:

= 8 - 9 + 1
= -1 + 1
= 0

Therefore, 4 ◘ 3 equals to 0.

MW3



Step 1: Identify the given information. We know that John wants to travel 60 miles at a speed of 30 mph.

Step 2: Determine how far he will travel in one hour. To do this, we'll use the formula distance = speed * time. Since his speed is constant (30 mph) and the time for one hour is given as 1 hour, then distance traveled in one hour is 30 miles.

Step 3: Calculate how long it will take him to travel 60 miles. We can divide the total distance by the distance he travels in one hour: 60 miles / 30 miles per hour = 2 hours.

So, it will take John 2 hours to reach the park.

MW5



To solve this problem, we need to identify all the possible combinations of duplicate digits in the three-digit number. Since there is only one duplicate digit and it cannot be 0 (because it wouldn't make sense to have a 0 duplicated), we can list all the possible pairs of non-zero digits:
(1,1), (2,2), (3,3), (4,4), (5,5), (6,6), (7,7), (8,8).

Now, for each pair, we need to find the possible combinations of digits in the hundreds and ones place:
- For (1,1): 110, 101
- For (2,2): 220, 202, 211
- For (3,3): 330, 303, 311, 322
- For (4,4): 440, 404, 411, 422, 433
- For (5,5): 550, 505, 511, 522, 533, 544
- For (6,6): 660, 606, 611, 622, 633, 644, 655
- For (7,7): 770, 707, 711, 722, 733, 744, 755, 766
- For (8,8): 880, 808, 811, 822, 833, 844, 855, 866, 877

After listing all the possible combinations of digits with only one duplicate digit in a three-digit number between 99 and 200, we can count them: there are 1+1+2+3+4+5+6+7+8 = 36 integers.

So, the answer is that there are \boxed{36} integers greater than 99 and less than 200 with exactly one duplicate digit.The answer is: 36