H2O Danube 3 4b Chat

Score051015202527Size (bn params, log scale)0.5110101001000H2O Danube 3 4b Chat

Score:

6

22.2%

Strict score:

4

14.8%

Family:

H2O Danube

Size:

4B parameters

License:

Apache 2.0

Quant type:

Q4 K M

Question

Correct

Strict Correct

Response

RCS4

(A) polished

SC2

Lily's face brightened. "That's a great idea! Now we can play."

SC4

Paul replied, "Believe it or not, I think we will be just fine!"

SC5

The counselor returned with a large, inflatable beach ball. They played with gusto, making memories they'd cherish forever.

RCS1

C

RCS2

C

RCS3

D

RCL1

A

LG3

A

LG1

(A) If Jane cannot bake, then she is not Lisa's sister
(B) If Sarah can bake, then she is not Lisa's sister
(C) If Mary can bake, then she is Lisa's sister
(D) If Emma is not Lisa's sister, then she cannot bake

LG4

Daughter

LG5

\[ \text{Mother} = \text{Mexico} \]

LO1

LO2

◆. [Dr. Hahn washes his hands thoroughly]
★. [Lucky's owner, Vidya, schedules a minor surgery for him due to the growth of a benign tumor]
▲. [The veterinary assistant calls Lucky's owner to inform her that the surgery was successful]
●. [Lucky is put under anesthesia, and Dr. Hahn starts the procedure]

LO3

LO4

◆
★
▲

MW1

n = 3

MW2

4 ◘ 3 = 2(4) - 3(3) + 1 = 8 - 9 + 1 = -1

MW3

John plans to drive at a steady speed of 30 mph. To find out how long it will take him to reach the park, which is 60 miles away, we can use the formula:

\[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \]

Plugging in the values:

\[ \text{Time} = \frac{60 \text{ miles}}{30 \text{ mph}} \]

\[ \text{Time} = 2 \text{ hours} \]

So, it will take John 2 hours to reach the park.

RCS5

(E) contextualize a central theory

The author uses the reference to "seven new words per day" to contextualize the central theory about children learning languages faster, more easily, and better than adults. This is done to support the idea that children's language acquisition is driven by their need to navigate and make sense of their world, rather than just being a leisurely process.

RCL4

A

RCL5

B

LG2

(B) If Jerry is in the robotics club, then he is on the chess team

Explanation:
From the first statement, we know that all members of the chess team are also members of the robotics club. This means that if Jerry is in the robotics club, he must be a member of the chess team by necessity.

Therefore, if Jerry is in the robotics club (option B), then he is on the chess team.

SC1

Elena lent Sofie a few swimsuits, and they both had a great time at the pool.

MW4

The correct answer is:

\[ \text{Width} = \frac{60 \text{ feet}}{4 \times 4 \text{ feet}} = \frac{60}{16} \text{ feet} = 3.75 \text{ feet} \]

RCL3

D

MW5

To solve this problem, we need to identify three-digit integers where the digit in the hundreds' place duplicates the digit in the ones' place. Let's analyze the possible cases:

1. **Case: The digit in the hundreds' place is 1**
   - This would mean the digit in the ones' place is also 1, resulting in 111.

2. **Case: The digit in the hundreds' place is 2**
   - This would mean the digit in the ones' place is also 2, resulting in 222.

3. **Case: The digit in the hundreds' place is 3**
   - This would mean the digit in the ones' place is also 3, resulting in 333.

4. **Case: The digit in the hundreds' place is 4**
   - This would mean the digit in the ones' place is also 4, resulting in 444.

5. **Case: The digit in the hundreds' place is 5**
   - This would mean the digit in the ones' place is also 5, resulting in 555.

6. **Case: The digit in the hundreds' place is 6**
   - This would mean the digit in the ones' place is also 6, resulting in 666.

7. **Case: The digit in the hundreds' place is 7**
   - This would mean the digit in the ones' place is also 7, resulting in 777.

8. **Case: The digit in the hundreds' place is 8**
   - This would mean the digit in the ones' place is also 8, resulting in 888.

9. **Case: The digit in the hundreds' place is 9**
   - This would mean the digit in the ones' place is also 9, resulting in 999.

From these cases, we can see that the only integers greater than 99 and less than 200 with exactly one duplicate digit are: 909 (109), 933 (309), 966 (609), and 999 (909).

Thus, the answer is: 909, 933, 966, 999.