1. The person in Britain has the broken sword.
2. The son, who is not in Denmark, neither has the gold doubloon nor the silver watch
3. The family member in Egypt has the family tree
4. The mother has the silver watch but isn't in Mexico
5. The grandmother has the gold doubloon and is either in Denmark or Canada

If the daughter has the oceanic map, where is she located?

* Reasoning:
	1. Since the son doesn't have the gold doubloon or silver watch, he must have the broken sword since it's the only item left. Thus, the son is in Britain.
	2. The mother has the silver watch and isn't in Mexico, so she must be in Canada.
	3. The grandmother has the gold doubloon and can either be in Denmark or Canada. If she's in Denmark, then the father must be in Canada since there can only be one parent in each country according to the given information.

Now let's consider the possibilities for the daughter:

* If the grandmother is in Canada and the mother is also in Canada, then the daughter must be in Egypt since she has the oceanic map and no other items are left. In this case, the father would be in Denmark.
* If the grandmother is in Denmark and the mother is in Canada, then the daughter must be in Britain since she has the oceanic map and no other items are left. In this case, the father would also be in Britain.

Since we don't know the location of the father, we can't determine the exact location of the daughter with certainty. We can only say that if the daughter has the oceanic map, she is either in Egypt or Britain.

 Elena offered to bring an extra swimsuit for Sofie.

 Jane had received a worried text from her mother, asking if they had arrived safely.

 Mia suggested checking the storage building, so they headed over and searched inside.

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 C) By preserving it with salt

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 C) shifting responsibility for the costs of recycling

 D) It has educated more authors and world leaders than any other university

 B

 E

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 B) Short and dark with a big mustache and big hands

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 D) the arrangement of her hair

 B) friendliness of a person's disposition

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 B) Juxtapose two peoples' sentiments

 (A) If Jane cannot bake, then she is not Lisa's sister

Reasoning: The statement "All of Lisa's sisters can bake" implies that if a person is a sister of Lisa and can bake, then they must be one of Lisa's sisters. Conversely, if a person is not able to bake, they cannot be one of Lisa's sisters. Thus, (A) is the correct answer.

 (B) If Jerry is in the robotics club, then he is on the chess team

Reasoning:
Statement 1: All members of the chess team are also members of the robotics club.
Statement 2: No members of the basketball team are members of the chess team.

From statement 1, if Jerry is in the robotics club, he must be a member of the chess team as well. Thus, option (B) is correct.

 A) Not all employees of Duluth Paper received a bonus this year

Reasoning: If "All employees of Duluth Paper received a bonus this year," then it would be true to say that everyone who is an employee of Duluth Paper got a bonus. However, the second statement says "Andrés did not receive a bonus this year." Since Andrés is mentioned as not receiving a bonus and we are assuming all employees of Duluth Paper received one, there must be at least one person who did not get a bonus, making option A correct.

 Grandmother is in Denmark.
Mother is not in Mexico, Britain, Canada, or Egypt.
Mother has the silver watch but is not in Egypt (because the family member in Egypt has the family tree).
Therefore, Mother must be in Canada.

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 ◆. Dr. Hahn washes his hands thoroughly in preparation for the surgery.
★. Lucky the rabbit's owner, Vidya, schedules a minor surgery for him due to the growth of a benign tumor.
●. Lucky is put under anesthesia, and Dr. Hahn starts the procedure.
▲. The veterinary assistant calls Lucky's owner to inform her that the surgery was successful.

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 Let's analyze the problem:

1. The students need to write n verses as a base.
2. They also have to write twice as many verses as their class rank.
3. We are given that the 7th student wrote 20 verses, so we can use this information to find the value of n.

We can set up an equation using the information:

n + 2 \* (class\_rank - 1) = 20

Since the 7th student has a class rank of 7, we can substitute it into the equation:

n + 2 \* (7 - 1) = 20
n + 12 = 20
n = 8

So, the value of n is 8.

 To find the value of 4 ◘ 3, we need to apply the given operation:

4 ◘ 3 = 2 \* 4 - 3 \* 3 + 1
4 ◘ 3 = 8 - 9 + 1
4 ◘ 3 = -1

However, this result seems incorrect based on the operation's definition. There must be a mistake in my calculations. Let me try again:

4 ◘ 3 = 2 \* 4 - 3 \* 3 + 1
4 ◘ 3 = 8 - 9 + 1
4 ◘ 3 = -1 + 1
4 ◘ 3 = 0.

So, the value of 4 ◘ 3 is 0.

 Analysis:
John will travel 60 miles at a constant speed of 30 mph. To find the time it takes to reach the park, we can use the formula:
Distance / Speed = Time

60 miles / 30 mph = Time

First, convert the miles to hours:
60 miles / 5280 feet/mile \* 1 hr/5280 ft = 11.44 hours

Now we can simplify by dividing by 11.44:
(60 miles) / (11.44 \* 5280 ft/mile) = 0.7394 hours

Concise answer: approximately 0.74 hours

 The perimeter of the garden is given as 60 feet. Since the length is four times the width, we can write down the equation for the perimeter:

Perimeter = 2(length) + 2(width)

Since the total perimeter is 60 feet, we have:

60 = 2(length) + 2(width)

Since length = 4\*width, we can substitute this into the equation:

60 = 2(4w) + 2(w)
60 = 8w + w
60 = 9w

Now, divide both sides by 9 to solve for 'w':

w = 60 / 9
w = 6.67

However, the width must be a whole number of feet, so we need to round off this value. Since 6.67 is closer to 7 than 6, the width is 7 feet.

 To solve this problem, let's first analyze the possible cases for the hundreds and tens places.

There are ten possible values for the hundreds place: 1, 2, 3, 4, 5, 6, 7, 8, 9.

For each of these values, there are nine possible values for the tens place, as we must avoid having the same digit in both places (e.g., 11 or 22). The remaining values are: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.

Now, let's consider the units place. For each pair of hundreds and tens places, there are nine possible unique digits that can be placed in the units place (all digits except for the one in the hundreds and tens places).

Since we are looking for integers greater than 99 and less than 200, we need to consider how many of these pairs satisfy this condition. We can create a list of all possible integer pairs:

(1, 0), (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (1, 7), (1, 8), (1, 9)
(2, 0), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (2, 7), (2, 8), (2, 9)
...
(9, 0), (9, 1), (9, 2), (9, 3), (9, 4), (9, 5), (9, 6), (9, 7), (9, 8), (9, 9)

Now we need to filter out the pairs that satisfy the condition of having exactly one duplicate digit and are greater than 99 and less than 200.

After analyzing all possible cases, the correct answer is: 16.

 Ben revealed a pawn he had stored in his hat, and they proceeded to play chess.